go 回文树板子
Apale 8/9/2021 golang
存个回文树的板子
(回文树yyds!!! 马拉车,狗都不写!!!)
SPOJ-NUMOFPAL (opens new window)
package main
import "fmt"
type node struct {
next []int
len, num int
suffixLink int
}
func makeNode(alphaNum int) node {
return node{
next: make([]int, alphaNum),
}
}
type palindromicAutomaton struct {
alphaNum int
s string //input
maxSuffID int //length of the max current SuffixPalindromicString
tree []node
}
func NewPalindromicAutomaton(s string, alphaNum int) *palindromicAutomaton {
tree := make([]node, 0, len(s))
tree = append(tree,
node{},
node{
next: make([]int, alphaNum),
len: -1,
num: 0,
suffixLink: 1,
},
node{ //odd root
next: make([]int, alphaNum),
len: 0,
num: 0,
suffixLink: 1,
},
)
return &palindromicAutomaton{
alphaNum: alphaNum,
s: s,
maxSuffID: 2,
tree: tree,
}
}
func (pa *palindromicAutomaton) pushBack(pos int) bool {
cur, curLen := pa.maxSuffID, 0
c := int(pa.s[pos] - 'a')
s := pa.s
for {
curLen = pa.tree[cur].len
if pos-1-curLen >= 0 && s[pos-1-curLen] == s[pos] {
break
}
cur = pa.tree[cur].suffixLink
}
if pa.tree[cur].next[c] != 0 {
pa.maxSuffID = pa.tree[cur].next[c]
return false
}
num := len(pa.tree)
pa.tree = append(pa.tree, makeNode(pa.alphaNum))
pa.maxSuffID = num
pa.tree[num].len = pa.tree[cur].len + 2
pa.tree[cur].next[c] = num
if pa.tree[num].len == 1 {
pa.tree[num].suffixLink = 2
pa.tree[num].num = 1
return true
}
for {
cur = pa.tree[cur].suffixLink
curLen = pa.tree[cur].len
if pos-1-curLen >= 0 && s[pos-1-curLen] == s[pos] {
pa.tree[num].suffixLink = pa.tree[cur].next[c]
break
}
}
pa.tree[num].num = 1 + pa.tree[pa.tree[num].suffixLink].num
return true
}
func main() {
var s string
fmt.Scanln(&s)
pa := NewPalindromicAutomaton(s, 26)
var ans int64
for i := range s {
pa.pushBack(i)
ans += int64(pa.tree[pa.maxSuffID].num)
}
fmt.Println(ans)
}
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